Salt A + S to B xrightarrow{BaCl_2} White pre | vedclass

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(C) $KO_2$ (Potassium superoxide) contains the superoxide ion $O_2^-$,which has one unpaired electron,making it paramagnetic in nature.The molar mass

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$KO_2$

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(C) $KO_2$ (Potassium superoxide) contains the superoxide ion $O_2^-$,which has one unpaired electron,making it paramagnetic in nature.The molar mass of $KO_2$ is $39 + 32 = 71 \, g/mol$.The percentage of $K$ in $KO_2$ is calculated as: $\frac{39}{71} 	imes 100 \approx 54.93\% \approx 55\%$.When $KO_2$ reacts with sulfur $(S)$,it forms a salt $B$ (potassium sulfate,$K_2SO_4$),which reacts with $BaCl_2$ to form a white precipitate of $BaSO_4$.

Salt $A + S \to B \xrightarrow{BaCl_2}$ White precipitate.
$A$ is paramagnetic in nature and contains about $55\% \, K$. Thus,$A$ is

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Salt $A + S \to B \xrightarrow{BaCl_2}$ White precipitate.$A$ is paramagnetic in nature and contains about $55\% \, K$. Thus,$A$ is